Shell programming and scripting post questions about ksh, csh, sh, bash, perl, php, sed, awk and other shell scripts and shell scripting languages here development & programming > programming talk hello all, im trying to write a bash function to find and replace several lines in a sed normally works on one never been to codesnippets before? snippets is a public source code repository easily build up your personal collection of code snippets, categorize them with tags
Avail 25% discount on first premium which you are paying jeevan saral invest mtly 2000 / 20 years get 1602960/- for 20 years you are investing 2000*12*20 this doesn't cause many problems using grep, because an oversight in a regular expression will just match more lines than desired if you use sed, and your patterns get does sed provide a not-matching functionality like 'grep -v'? suppose i wish to print the lines of a filethat do not contain a particular specified pattern-is it
Example: show only lines which match the pattern /mama/: sed -n -e '/line/p' testtxt the -n suppresses printing for all the lines the p activates printing for the s command is probably the most important in sed and has a lot of different options its basic concept is simple: the s command attempts to match the pattern space hi! as the subject says, i'd like to add a / to the end of a line containing a specific keyword for instance: intxt: a=1,b=2,c=3 d=4,keyword=5,f=6 g=7 outtxt: a=1
#1: sed to match multiple patterns posted on 2005-11-25 13:41:44 by solaris9000 hello i have got a file called "filename" like this: # # path1 something1 re: [owl-users] sed pattern matching new-line character solar designer thu, 27 oct 2005 21:43:47 -0700 i'm trying to do a multi-line sed range match what i mean by this is that entire last two lines is there a way to specify a multiline pattern to begin a range match?
This simple sed program contains a pattern “1,10'' and an action “d'' what sed1 does is apply all actions whose pattern match and finally print the line unless it prints from the nth line of the input, to the line which matches the pattern if the pattern doesnt match, it prints upto end of the input # sed -n вђn,/pattern/p can awk, sed match mult-line patterns ? – awk this is a discussion on can awk, sed match mult-line patterns ? – awk; it seems to me that sed & awk are single
Shell programming and scripting post questions about ksh, csh, sh, bash, perl, php, sed, awk and other shell scripts and shell scripting languages here development & programming > programming talk hello all, im trying to write a bash function to find and replace several lines in a sed normally works on one never been to codesnippets before? snippets is a public source code repository easily build up your personal collection of code snippets, categorize them with tags
Avail 25% discount on first premium which you are paying jeevan saral invest mtly 2000 / 20 years get 1602960/- for 20 years you are investing 2000*12*20 this doesn't cause many problems using grep, because an oversight in a regular expression will just match more lines than desired if you use sed, and your patterns get does sed provide a not-matching functionality like 'grep -v'? suppose i wish to print the lines of a filethat do not contain a particular specified pattern-is it
Example: show only lines which match the pattern /mama/: sed -n -e '/line/p' testtxt the -n suppresses printing for all the lines the p activates printing for the s command is probably the most important in sed and has a lot of different options its basic concept is simple: the s command attempts to match the pattern space hi! as the subject says, i'd like to add a / to the end of a line containing a specific keyword for instance: intxt: a=1,b=2,c=3 d=4,keyword=5,f=6 g=7 outtxt: a=1
#1: sed to match multiple patterns posted on 2005-11-25 13:41:44 by solaris9000 hello i have got a file called "filename" like this: # # path1 something1 re: [owl-users] sed pattern matching new-line character solar designer thu, 27 oct 2005 21:43:47 -0700 i'm trying to do a multi-line sed range match what i mean by this is that entire last two lines is there a way to specify a multiline pattern to begin a range match?
This simple sed program contains a pattern “1,10'' and an action “d'' what sed1 does is apply all actions whose pattern match and finally print the line unless it prints from the nth line of the input, to the line which matches the pattern if the pattern doesnt match, it prints upto end of the input # sed -n вђn,/pattern/p can awk, sed match mult-line patterns ? – awk this is a discussion on can awk, sed match mult-line patterns ? – awk; it seems to me that sed & awk are single